# Determine the mass of aluminum oxide that is formed in oxygen oxidation reactions. The mass of aluminum is 48 grams.

June 30, 2021 | education

| m (Al) = 48 g.

Determine the mass of aluminum oxide. We write down the equation of reactions.

4Al + 3O2 = 2Al2O3.

We find the amount of aluminum substance, for this we use the following formula.

n = m / M.

Where n is the amount of substance.

m is the mass of the substance.

M is the molar mass of the substance.

M (Al) = 27 g / mol.

n = 48 g / 27 g / mol = 1.7 mol.

Further, according to the reaction equation, we find the amount of the substance of aluminum oxide.

1.7 mol Al – х mol Al2O3.

4 mol Al – 2 mol Al2O3.

X = 1.7 mol × 2 mol ÷ 4 mol = 0.85 mol.

Next, we find the mass of aluminum.

M (Al2O3) = 27 × 2 + 16 × 3 = 102 g / mol.

m = n × M = 0.85 mol × 102 g / mol = 86.7 g.

Answer: m (Al2O3) = 86.7 g.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.