Determine the mass of aluminum that can be burned in 13.44 liters of oxygen

Elemental aluminum reacts with oxygen gas to form alumina. The reaction is described by the following chemical reaction equation:

4Al + 3O2 = 2Al2O3;

Let’s calculate the chemical amount of oxygen. To do this, we divide its volume by the volume of 1 mole of gas (filling volume 22.4 liters).

N O2 = 13.44 / 22.4 = 0.6 mol;

In such an amount of oxygen, 0.6 x 4/3 = 0.8 mol of aluminum can be burned.

Let’s determine its weight. For this purpose, we multiply the amount of the substance by its molar weight.

M Al = 27 grams / mol;

m Al = 0.8 x 27 = 21.6 grams;