Aluminum reacts with hydrochloric acid. In this case, an aluminum chloride salt can be obtained and hydrogen gas bubbles are released. The reaction is described by the following equation.
Al + 3HCl = AlCl3 + 3/2 H2;
Determine the chemical amount of the evolved hydrogen gas.
For this purpose, we find the ratio of its volume to the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).
N H2 = 67.2 / 22.4 = 3 mol;
To obtain such an amount of hydrogen, it is required to dissolve 3 x 2/3 = 2 mol of aluminum.
Let’s find its mass.
M Al = 27 grams / mol;
m Al = 27 x 2 = 54 grams;
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