Determine the mass of aluminum that has reacted with hydrochloric acid if 67.2 liters of hydrogen are released.

Aluminum reacts with hydrochloric acid. In this case, an aluminum chloride salt can be obtained and hydrogen gas bubbles are released. The reaction is described by the following equation.

Al + 3HCl = AlCl3 + 3/2 H2;

Determine the chemical amount of the evolved hydrogen gas.

For this purpose, we find the ratio of its volume to the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).

N H2 = 67.2 / 22.4 = 3 mol;

To obtain such an amount of hydrogen, it is required to dissolve 3 x 2/3 = 2 mol of aluminum.

Let’s find its mass.

M Al = 27 grams / mol;

m Al = 27 x 2 = 54 grams;

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