Determine the mass of aluminum that will be released when hydrogen reacts with 200 g of aluminum oxide containing 49% impurities.

given:
m mixture (Al2O3) = 200 g
w (Al2O3) = 49%
to find:
m substance (Al)
decision:
2Al2O3 + 6H2 = 6H20 + 4Al
m substance (Al2O3) = w * m mixture = 0.49 * 200 g = 98 g
n (Al2O3) = m: M = 98 g * 102 g / mol = 1 mol
n (Al2O3): n (Al) = 2: 4
n (Al) = 2 mol
m (Al) = m * M = 2 mol * 27 g / mol = 54 g
answer: 54 g



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