Determine the mass of aluminum that will react with 8.96L of oxygen.

Metallic aluminum reacts with oxygen to form alumina. The reaction is described by the following chemical reaction equation:
4Al + 3O2 = 2Al2O3;
Let’s determine the chemical amount of oxygen. For this purpose, we divide its volume by the volume of 1 mole of gas (which is 22.4 liters).
N O2 = 8.96 / 22.4 = 0.4 mol;
In such an amount of oxygen, 0.4 x 4/3 = 0.5333 mol of aluminum can be burned.
Let’s calculate its weight. To do this, multiply the amount of the substance by its molar weight.
M Al = 27 grams / mol;
m Al = 0.5333 x 27 = 14.3999 grams.