Determine the mass of ammonium chloride that can be obtained from 425g. 50% ammonia.

1. Let’s compose the reaction equation:

NH3 + HCl = NH4Cl;

2.Calculate the mass of ammonia:

m (NH3) = w (NH3) * m (solution) = 0.5 * 425 = 212.5 g;

3. find the chemical amounts of ammonia and ammonium chloride:

n (NH3) = m (NH3): M (NH3);

M (NH3) = 14 + 3 = 17 g / mol;

n (NH3) = 212.5: 17 = 12.5 mol;

n (NH4Cl) = n (NH3) = 12.5 mol;

4.determine the mass of ammonium chloride:

m (NH4Cl) = n (NH4Cl) * M (NH4Cl);

M (NH4Cl) = 14 + 4 + 35.5 = 53.5 g / mol;

m (NH4Cl) = 12.5 * 53.5 = 668.75 g.

Answer: 668.75 g.