Determine the mass of barium carbonate, which reacted with an excess of hydrochloric acid

| September 4, 2021 | education

Determine the mass of barium carbonate, which reacted with an excess of hydrochloric acid, if 20 liters of carbon dioxide were released, and the product yield was 90%.

To solve the problem, we write down the equation of the process:

BaCO3 + 2HCl = BaCl2 + CO2 + H2O – ion exchange, carbon dioxide is released;

We make calculations:
M (BaCO3) = 197.3 g / mol;

M (CO2) = 44 g / mol.

Proportion:
1 mole of gas at normal level – 22.4 liters;

X mol (CO2) -20 L from here, X mol (CO2) = 1 * 20 / 22.4 = 0.89 mol.

Y (BaCO3) = 0.89 mol since the amount of substances is 1 mol.

We find the mass of the starting material, taking into account the product yield:
m (BaCO3) = Y * M = 0.89 * 197.3 = 175.6 g (theoretical weight);

W = m (practical) / m (theoretical) * 100;

m (BaCO3) = 0.90 * 175.6 = 158.04 g (practical weight).

Answer: you need barium carbonate weighing 158.04 g



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.