Determine the mass of barium chloride, which was formed by the interaction of 40 g of Ba (OH) 2 with hydrochloric acid

univerkov | December 9, 2020 | education

Ba (OH) 2 + 2HCl -> BaCl2 + H2O m (Ba (OH) 2) = 40g
m (BaCl2) -?
n (Ba (OH) 2) = m / M = 40g / 170g / mol = 0.235 mol n (Ba (OH) 2) = n (BaCl2) = 0.235 mol m (BaCl2) = 0.235 mol * 208g / mol ~ 49g
Answer: 49g

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