Determine the mass of barium required to obtain 306 g of barium when it interacts with oxygen

univerkov | January 17, 2021 | education

Given:
m (BaO) = 306 g
To find:
m (Ba)
Decision:
2Ba + O2 = 2BaO
n (BaO) = m / M = 306 g / 153 g / mol = 2 mol
n (BaO): n (Ba) = 1: 1
n (Ba) = 2 mol
m (Ba) = n * M = 2 mol * 137 g / mol = 274 g
Answer: 274 g

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