Determine the mass of boric acid, which is obtained by the interaction of 6.8 g of boron with 27 ml of 2 M sulfuric acid solution.

Determine the mass of boric acid, which will result from the interaction of 6.8 g of boron with 27 ml of 2 M sulfuric acid solution
c (H2SO4) = 2/2 = 1 (mol / L)
27ml = 0.027 (L)
n (H2SO4) = c (H2SO4) * V (H2SO4)
n (H2SO4) = 0.027 (mol)
B + H2SO4 = H3BO3 + SO2 + H2O
n (B) = m (B): M (B)
M (B) = 11 (g / mol)
n (B) = 6.8 / 11 = 0.6 (mol)
n (B) = n (H3BO3) = 0.6 (mol)
M (H3BO3) = 3 + 11 + 48 = 62 (g / mol)
m (H3BO3) = M (H3BO3) * n (H3BO3)
m (H3BO3) = 0.6 * 62 = 37.2 (g)