The decomposition reaction of calcium carbonate is described by the following chemical reaction equation:
CaCO3 = CaO + CO2;
From 1 mole of chalk, 1 mole of calcium oxide is synthesized. This releases 1 mole of carbon dioxide.
Let’s calculate the chemical amount of available limestone.
M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;
N CaCO3 = 20/100 = 0.2 mol;
The same amount of calcium oxide will be obtained.
We calculate the weight of 0.2 mol of calcium oxide.
M CaO = 40 + 16 = 56 grams / mol;
m CaO = 0.2 x 56 = 11.2 grams;
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