Determine the mass of carbon monoxide (CO), which contains the same number of molecules as there are atoms in 8g.

N CuSO4 = 8 g: 160 g / mol = 0.05 mol. Atoms in one molecule of copper sulfate 6 pcs. According to the conditions of the problem, the amount of CO is 0.05 * 6 = 0.3 mol. The volume of gas is 0.3 mol * 22.4 l / mol = 6.71 l.



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