Determine the mass of carbon monoxide (IV), which is obtained by combustion of 5 mol of methane?

CH4 + O2 = CO2 + H2O
It is necessary to equalize this reaction
CH4 + 2O2 = CO2 + 2H2O
It can be seen from the equation that the amount of methane is equal to the amount of carbon dioxide, we write
n (CH4) = n (CO2) = 5 mol
And since we know the amount, we can easily find the mass of carbon dioxide by the formula
m (CO2) = M * n
M (CO2) = 12 + 16 * 2 = 44 (g / mol)
m (CO2) = 5 * 44 = 220 (g)