Determine the mass of copper sulfate, which is formed by dissolving 40 g of copper oxide in sulfuric acid.

Given:
m (CuO) = 40 g
To find:
m (CuSO4)
Decision:
H2SO4 + CuO = CuSO4 + H2O
n (CuO) = m / M = 40 g / 80 g / mol = 0.5 mol
n (CuO): n (CuSO4) = 1: 1
n (CuSO4) = 0.5 mol
m (CuSO4) = n * M = 0.5 mol * 160 g / mol = 80 g
Answer: 80 g



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