Determine the mass of copper sulfate, which will be required to obtain copper hydroxide with an amount of 0.15

| August 12, 2021 | education

Determine the mass of copper sulfate, which will be required to obtain copper hydroxide with an amount of 0.15 mol of the substance, when interacting with potassium hydroxide.

Let’s implement the solution:
1. By the condition of the problem, we write the equation:
X g -? Y = 0.15 mol;
CuSO4 + 2KOH = Cu (OH) 2 + K2SO4 – ion exchange, obtained copper hydroxide (precipitate), potassium sulfate;
2. Calculations of molar masses:
M (CuSO4) = 159.5 g / mol;
M Cu (OH) 2 = 97.5 g / mol.
3. Find the mass of the sediment:
We take into account that the number of moles of CuSO4, Cu (OH) 2 are equal, since according to the equation, 1 mole each.
Y (CuSO4) = 0.15 mol;
m (CuSO4) = Y * M = 0.15 * 159.5 = 23.93 g.
Answer: the mass of copper sulfate is 23.93 g.



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