Determine the mass of copper sulfide (2) formed as a result of the interaction

| February 16, 2021 | education

Determine the mass of copper sulfide (2) formed as a result of the interaction of 5 mol of copper sulfate (2) with hydrosulfuric acid taken in excess.

n (CuSO4) = 5 mol.
Determine the mass of copper sulfide obtained as a result of the reaction.
We write down the equation of reactions.
СuSO4 + H2S = CuS + H2SO4
Using the reaction equation, we find the amount of copper sulfide substance.
5 mol СuSO4 – х mol CuS
1 mol CuSO4 – 1 mol CuS
Find the unknown value of x.
X = 5 * 1: 1 = 5 mol CuS
Next, we find the mass of copper sulfide.
n = m / M.
Where n is the amount of substance.
m is the mass of the substance.
M is the molar mass of the substance.
m = n * M.
M (CuS) = 64 + 32 = 96 g / mol.
m = 5 * 96 = 480 g.
The mass of copper sulfide obtained as a result of the reaction is 480 g.
Answer: m = 480 g.



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