Determine the mass of copper that can be displaced by aluminum from 450 g of a 16% copper (II) sulfate solution.

Determine the mass of copper that can be displaced by aluminum from 450 g of a 16% copper (II) sulfate solution. I get 29, 25 on the Internet everywhere is not the same, how is it correct?

Given:
m (CuSO4) solution = 450g
w (CuSO4) = 16%
Define:
m (Cu) -?
3CuSO4 + 2Al -> Al2 (SO4) 3 + 3Cu
M (CuSO4) = 63.5 = 32 + 16 * 4 = 159.5 g / mol
M (Cu) = 63.5 g / mol
m (CuSO4) pure = 450g * 16% = 72g
The amount of substance v (CuSO4) = 72g / 159.5g / mol = 0.45mol
Based on the reaction equation, it can be seen that v (CuSO4) is related to v (Cu) as 3: 3, that is, as 1: 1. So v (Cu) = 0.45 mol
m (Cu) = 0.45 mol * 63.5 g / mol = 25.57 g