Determine the mass of copper that can be obtained by reducing copper (II) oxide with coal weighing 12 grams

Determine the mass of copper that can be obtained by reducing copper (II) oxide with coal weighing 12 grams, if the mass fraction of the copper yield is 85% of the theoretical.

The copper reduction reaction can be written as an equation:

2CuO + C = 2Cu + CO2

Find the mass of copper assuming 100% yield.

Molar mass of copper = 63.5 g / mol; molar mass of carbon = 12 g / mol

Based on the reaction equation, we will compose the proportion:

X g of copper corresponds to 12 g of coal as

63.5 g / mol of copper corresponds to 12 g / mol of coal

X = (12 * 63.5) / 12 = 63.5 g of copper – theoretical yield.

Let us now find a practical copper yield:

M = 63.5 * 0.85 = 54 g – the practical yield of the reaction.

Answer: the mass of copper is 54 g.