Determine the mass of copper that can be obtained from 40gr of copper oxide by reduction with hydrogen.

Copper oxide is reduced with hydrogen gas. This synthesizes metallic copper and water. This reaction is described by the following equation:

CuO + H2 = Cu + H2O;

Copper oxide reacts with hydrogen in equal molar amounts. At the same time, the same equal amounts of copper and water are synthesized.

Let’s determine the chemical amount of copper oxide.

To do this, divide the weight of the oxide by the weight of 1 mole of oxide.

M CuO = 64 + 16 = 80 grams / mol;

N CuO = 40/80 = 0.5 mol;

Thus, 0.5 mol of copper oxide can be reduced and 0.5 mol of copper can be synthesized.

Its mass will be equal to:

M Cu = 64 grams / mol;

m Cu = 64 x 0.5 = 32 grams;