Determine the mass of iron obtained by reducing 40 g of iron (III) oxide with hydrogen.

The reduction reaction of iron oxide with hydrogen is described by the following chemical reaction equation:

Fe2O3 + 3H2 = 2Fe + 3H2O;

From 1 mole of metal oxide, 1 mole of metal can be reduced.

Let’s calculate the chemical amount of a substance in 40 grams of iron oxide.

M Fe2O3 = 56 x 2 + 16 x 3 = 160 grams / mol;

N Fe2O3 = 40/160 = 0.25 mol;

During the reaction, 0.25 x 2 = 0.5 mol of iron will be obtained.

Let’s calculate its weight.

M Fe = 56 grams / mol;

m Fe = 56 x 0.5 = 28 grams;