Determine the mass of KCl formed as a result of the chemical reaction of the interaction of 276 grams of potassium
Determine the mass of KCl formed as a result of the chemical reaction of the interaction of 276 grams of potassium carbonate K2CO3 with hydrochloric acid: K2CO3 + 2HCl = 2KSl + H2CO3
Let’s execute the solution:
1. Let us write the equation according to the problem statement:
m = 276 g. m -?
K2CO2 + 2HCl = 2KCl + H2O + CO2 – ion exchange reaction, potassium chloride salt, carbon monoxide, water are released;
2. Calculation of the molar masses of substances:
M (K2CO3) = 138 g / mol;
M (KCl) = 74.5 g / mol.
3. Determine the number of moles of potassium carbonate, if the mass is known:
Y (K2CO3) = m / M = 276/138 = 2 mol.
4. Let’s make the proportion:
2 mol (K2CO3) – X mol (KCl);
-1 mol – 2 mol from here, X mol (KCl) = 2 * 2/1 = 4 mol.
5. Let’s find the mass of the reaction product – KCl:
m (KCl) = Y * M = 4 * 74.5 = 298 g.
Answer: C, 298
