Determine the mass of lithium oxide that can be obtained from 56 g of lithium.

Given:
m (Li) = 56 g
To find:
m (Li2O)
Decision:
4Li + O2 = 2Li2O
n (Li) = m / M = 56 g / 7 g / mol = 8 mol
n (Li): n (Li2O) = 2: 1
n (Li2O) = 8 mol / 2 = 4 mol
m (Li2O) = n * M = 4 mol * 30 g / mol = 120 g
Answer: 120 g



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