Determine the mass of mercury that will be required to react with oxygen to obtain 0.1 mol of mercury oxide (HgO)?

univerkov | August 22, 2021 | education

n (Нg) = 0.1 mol
m (Нg) -?
2Hg + O2 = 2HgO
n (Hg) = n (HgO) = 0.1 mol;
n (О2) = 1/2 n (НgО) = 0.5 * 0.1 = 0.05 mol;
m (O2) = n (O2) * M (O2) = 0.05 * 32 = 1.6 gr.
m (Hg) = n (Hg) * M (Hg) = 0.1 * 201 = 20.1 gr.
Answer: 20.1 grams of mercury is needed for the reaction

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