Determine the mass of methanol that can be obtained as a result of the interaction

Determine the mass of methanol that can be obtained as a result of the interaction of carbon monoxide (II) with a volume of 3 liters with hydrogen.

Given:
V (CO) = 3 l
Find: m (CH3OH)
Decision:
CO + 2H2 = CH3OH
n (CO) = V / Vm = 3 L / 22.4 L / mol = 0.13 mol
n (CO): n (CH3OH) = 1: 1
n (CH3OH) = 0.13 mol
m (CH3OH) = n * M = 0.13 mol * 32 g / mol = 4.16 g
Answer: 4.16 g



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