In this task you will need to determine the mass of nitric acid. First, you need to draw up an equation for a chemical reaction.
2HNO3 + CuO = Cu (NO3) 2 + H2O.
It is necessary to make a proportion.
Determine the molar mass of copper oxide and nitric acid.
M (HNO3) = 1 + 14 + 16 * 3 = 63 g / mol.
M (CuO) = 80 g / mol.
X g of nitric acid – 320 g of copper oxide.
2 * 63 g / mol – 80 g / mol.
X = 2 * 63 * 320/80 = 504 g.
This means that the mass of nitric acid is 504 grams.
Answer: 504 g.
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