Determine the mass of nitrogen required to obtain 170 g of ammonia, if the yield of the reaction product is 30 percent

Let’s implement the solution:
1. According to the condition of the problem, we compose the equation:
X g -? m = 170 g. W = 30%

N2 + H2 = 2NH3 – compounds, ammonia was obtained;
2. Calculations:
M (N2) = 28 g / mol;
M (NH3) = 17 g / mol.
3. We find the practical mass of the product:
m (NH3) = 0.30 * 170 = 51 g;
Y (NH3) = m / M = 51/17 = 3 mol.
4. Proportion:
X mol (N2) – 3 mol (NH3);
-1 mol -2 mol hence, X mol (N2) = 1 * 3/2 = 1.5 mol;
M (N2) = Y * M = 1.5 * 28 = 42 g.
5. Determine the mass of the original substance:
m (N2) = M * Y = 28 * 1.5 = 42 g.
Answer: to carry out the process, nitrogen with a mass of 42 g is required.