Determine the mass of oxygen occupying a volume of 600 liters at a temperature of 300K and normal atmospheric pressure.

To determine the mass of oxygen, we use the Mendeleev-Clapeyron equation:

PV = mRT / M,

where P is the pressure,

V – volume,

R – universal gas constant,

T – temperature,

M is the molar weight of molecular oxygen (0.032 kg / mol).

m = PVM / RT = (0.6 m ^ 3 * 101 325 Pa * 0.032 kg / mol) / 8.314 J / (mol * K) * 300 K = 0.78 kg.

Answer: 0.78 kg.



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