Determine the mass of oxygen occupying a volume of 600 liters at a temperature of 300K and normal atmospheric pressure.
July 15, 2021 | education
| To determine the mass of oxygen, we use the Mendeleev-Clapeyron equation:
PV = mRT / M,
where P is the pressure,
V – volume,
R – universal gas constant,
T – temperature,
M is the molar weight of molecular oxygen (0.032 kg / mol).
m = PVM / RT = (0.6 m ^ 3 * 101 325 Pa * 0.032 kg / mol) / 8.314 J / (mol * K) * 300 K = 0.78 kg.
Answer: 0.78 kg.
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