Determine the mass of oxygen that will be required to obtain magnesium oxide weighing 8 grams.
August 30, 2021 | education|
1. Let’s compose the equation of magnesium oxidation:
2Mg + O2 = 2MgO;
2.Calculate the chemical amount of magnesium oxide:
n (MgO) = m (MgO): M (MgO);
M (MgO) = 24 + 16 = 40 g / mol;
n (MgO) = 8: 40 = 0.2 mol;
3. according to the reaction equation, the amount of oxygen is half that of magnesium oxide, we determine the amount of oxide:
n (O2) = n (MgO): 2 = 0.2: 2 = 0.1 mol;
4.Calculate the mass of oxygen:
m (O2) = n (O2) * M (O2) = 0.1 * 32 = 3.2 g.
Answer: 3.2 g.
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