Determine the mass of phosphorus oxide formed by the interaction of 50 g of phosphorus with oxygen.

The synthesis reaction of phosphorus oxide is described by the following chemical reaction equation:

4P + 5O2 = 2P2O5;

4 moles of phosphorus react with 5 moles of oxygen. In this reaction, 2 moles of phosphorus oxide are synthesized.

Let’s calculate the chemical amount of a substance in phosphorus weighing 9.1 grams.

M P = 31 grams / mol;

N P = 50/31 = 1.613 mol;

From this amount of phosphorus, it is possible to synthesize 1.613 / 2 = 0.8065 mol of its oxide.

Let’s calculate its weight.

To do this, multiply the amount of the substance by its molar weight.

M P2O5 = 31 x 2 + 16 x 5 = 142 grams / mol;

m P2O5 = 142 x 0.8065 = 114.523 grams;