# Determine the mass of potassium hydroxide required to completely neutralize 400 g of a 9.8% sulfuric acid solution.

1.Let’s find the mass of acid in the solution.

W = m (substance): m (solution) × 100%,

hence m (substance) = (m (solution) × w): 100%.

m (substance) = (400 g × 9.8%): 100% = 39.2 g.

Let’s find the amount of aminoacetic acid substance by the formula:

n = m: M.

M (H2SO4) = 2 + 32 + 64 = 98 g / mol.

n = 39.2 g: 98 g / mol = 0.4 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

H2SO4 + 2 KOH = K2SO4 + H2O.

According to the reaction equation, 1 mol of sulfuric acid accounts for 2 mol of potassium hydroxide. Substances are in quantitative ratios

12.

The amount of the KOH substance will be 2 times more than the amount of the acid substance.

2n (H2SO4) = n (KOH) = 2 × 0.4 = 0.8 mol.

Find the mass of potassium hydroxide by the formula:

m = n × M,

M (KOH) = 39 + 1 + 16 = 56 g / mol.

m = 0.8 mol × 56 g / mol = 44.8 g.

Answer: 44.8 g.