Determine the mass of potassium phenolate obtained by the interaction of 9 g of potassium hydroxide and 14.1 g of phenol?

univerkov | November 30, 2020 | education

С6H5OH + KOH => C6H5OK + H2O phenol is taken in excess, therefore, we calculate by potassium hydroxide n (KOH) = 9/56 = 0.16 mol n (C6H5OK) = n (KOH) = 0.16 mol from here we find the mass of phenolate m (C6H5OK ) = 0.16 * 132 = 21.12 g

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