Determine the mass of potassium sulfate obtained by the interaction of 560th 20% potassium

Determine the mass of potassium sulfate obtained by the interaction of 560th 20% potassium hydroxide solution and 980 g of 10% sulfuric acid solution.

1. Potassium sulfate is obtained by the reaction:

2KOH + H2SO4 = K2SO4 + 2H2O;

2. Calculate the masses of the starting materials:

m (KOH) = w (KOH) * m (solution KOH) = 0.2 * 560 = 112 g;

m (H2SO4) = w (H2SO4) * m (solution H2SO4) = 0.1 * 980 = 98 g;

3. Let’s calculate the chemical amounts of reagents:

n (KOH) = m (KOH): M (KOH);

M (KOH) = 39 + 17 = 56 g / mol;

n (KOH) = 112: 56 = 2 mol;

n (H2SO4) = m (H2SO4): M (H2SO4);

M (H2SO4) = 2 + 32 + 4 * 16 = 98 g / mol;

n (H2SO4) = 98: 98 = 1 mol;

4. Both reagents are taken in sufficient quantities, so you can use the data of any substance to find the amount of potassium sulfate:

n (K2SO4) = n (H2SO4) = 1 mol;

5. Determine the mass of the resulting sulfate:

m (K2SO4) = n (K2SO4) * M (K2SO4);

M (K2SO4) = 39 * 2 + 32 + 4 * 16 = 174 g / mol;

m (K2SO4) = 1 * 174 = 174 g.

Answer: 174 g.