Determine the mass of potassium sulfate, which is formed by the interaction of 200 g of solution with a mass fraction of KOH

Determine the mass of potassium sulfate, which is formed by the interaction of 200 g of solution with a mass fraction of KOH of 11.2% and 300 g of sulfuric acid solution with a mass fraction of 19.6%.

Given:
m p (KOH) = 200 g
w (KOH) = 11.2% = 0.112
m p (H2SO4) = 300 g
w (H2SO4) = 19.6% = 0.196
Find: m (K2SO4)
Decision:
2KOH + H2SO4 = K2SO4 + 2H2O
m in (KOH) = m p * w = 200 g * 0.112 = 22.4 g
m in (H2SO4) = m p * w = 300 g * 0.196 = 58.8 g
m in (K2SO4) = 22.4 g + 58.8 g = 81.2 g
Answer: 81.2 g