Determine the mass of precipitates obtained by the interaction of H2SO4 with a mass equal to 200 g, with BaCL

univerkov | January 17, 2021 | education

Given:
m (H2SO4) = 200 g
To find:
m (BaSO4)
Decision:
H2SO4 + BaCl2 = BaSO4 + 2HCl
n (H2SO4) = m / M = 200 g / 98 g / mol = 2 mol
n (H2SO4): n (BaSO4) = 1: 1
n (BaSO4) = 2 mol
m (BaSO4) = n * M = 2 mol * 233 g / mol = 466 g
Answer: 466 g

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