Determine the mass of pure Fe2O3 in 1 ton of magnetic iron ore containing 24% of impurities.
| September 5, 2021 | education
Given: m (magnetic iron ore) – 1 t
ω (impurities) – 24%
find: m (Fe2O3)
ω = m (Fe2O3) / m (magnetic iron ore) * 100%
24% = x / 1000 * 100%
X = 24 * 1000/100
X = 240kg
Answer: m (Fe2O3) = 240kg
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