Determine the mass of salt that is formed by the interaction of 60 g of sodium hydroxide with nitric acid.

Given:

m1 (NaOH) = 60 g.

To find:

m2 (NaNO3) =?

Solution:

1) We compose the equation of the chemical reaction:

NaOH + HNO3 = NaNO3 + H2O.

2) The formula for solving the problem: m1: m2 = M1: M2, hence m2 = (m1 x M2): M1.

3) Find the molecular weights of sodium hydroxide and its salt:

M1 (NaOH) = 23 + 16 + 1 = 40 g / mol;

M2 (HNO3) = 23 + 14 + (16 x 3) = 85 g / mol.

4) Substitute the values:

60 g: 40 g / mol = m2: 85 g / mol,

m2 = (60 x 85): 40 = 127.5 g.

Answer: m2 (NaNO3) = 127.5 g.