Determine the mass of sediment that forms when 49 g of a 5% solution of sulfuric acid with barium hydroxide are combined.

univerkov | January 17, 2021 | education

Given:
m p (H2SO4) = 49 g
w (H2SO4) = 5% = 0.05
Find: m (BaSO4)
Decision:
H2SO4 + Ba (OH) 2 = BaSO4 + 2H2O
m in (H2SO4) = w * m p = 0.05 * 49 g = 2.45 g
n (H2SO4) = m / M = 2.45 g / 98 g / mol = 0.025 mol
n (H2SO4): n (BaSO4) = 1: 1
n (BaSO4) = 0.025 mol
m (BaSO4) = n * M = 0.025 mol * 233 g / mol = 5.825 g
Answer: 5.825 g

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