Determine the mass of slaked lime (Ca (OH) 2, which is formed if 200 g of quicklime (Ca O)

Determine the mass of slaked lime (Ca (OH) 2, which is formed if 200 g of quicklime (Ca O) is poured with the required amount of water.

The reaction for the synthesis of slaked lime (calcium hydroxide) from unslaked lime (calcium oxide) is described by the following equation:
CaO + H2O = Ca (OH) 2;
In the course of the reaction, 1 molecule of water is attached to 1 molecule of calcium oxide.
Let’s calculate the chemical amount of a substance in 56 kilograms of calcium oxide.
To do this, divide the available weight of the oxide by the weight of one mole of oxide.
M CaO = 40 +16 = 56 grams / mol;
N CaO = 200/56 = 3.571 mol;
The same amount of calcium hydroxide will be obtained. Let’s calculate its weight.
To do this, multiply the amount of hydroxide available by the weight of one mole of hydroxide.
M Ca (OH) 2 = 40 + (16 + 1) x 2 = 74 grams / mol;
m Ca (OH) 2 = 3.571 x 74 = 264.2 grams;