Determine the mass of sodium hydroxide and the volume of water required to prepare 700 g of an 8% solution.

Knowing that in 700 g solution the mass fraction of sodium hydroxide should be 8%, we find the mass of NaOH.

m (NaOH) = 8 * 700/100 = 56 g

m (H2O) = 700 – 56 = 644 g

Since the density of water is 1 g / ml, the volume of water is 644 ml.



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