Determine the mass of sodium hydroxide solution with a mass fraction of 0.1, which is necessary for interaction

Determine the mass of sodium hydroxide solution with a mass fraction of 0.1, which is necessary for interaction with carbon dioxide to form an acidic salt formed during the complete combustion of methane with a volume of 5.6 liters.

Given:
ω (NaOH) = 0.1
V (CH4) = 5.6 L

Find:
m solution (NaOH) -?

1) CH4 + 2O2 => CO2 + 2H2O;
CO2 + NaOH => NaHCO3;
2) n (CH4) = V (CH4) / Vm = 5.6 / 22.4 = 0.25 mol;
3) n (CO2) = n (CH4) = 0.25 mol;
4) n (NaOH) = n (CO2) = 0.25 mol;
5) M (NaOH) = Mr (NaOH) = Ar (Na) * N (Na) + Ar (O) * N (O) + Ar (H) * N (H) = 23 * 1 + 16 * 1 + 1 * 1 = 40 g / mol;
6) m (NaOH) = n (NaOH) * M (NaOH) = 0.25 * 40 = 10 g;
7) m solution (NaOH) = m (NaOH) / ω (NaOH) = 10 / 0.1 = 100 g.

Answer: The mass of the NaOH solution is 100 g.