Determine the mass of sodium oxide that is formed in the sodium reaction of 11.2 liters of oxygen.

The sodium oxidation reaction is described by the following chemical reaction equation:

2Na + ½ O2 = Na2O;

From 2 mol of sodium, 1 mol of sodium oxide is synthesized. This consumes 0.5 mol of oxygen.

Let’s calculate the chemical amount of a substance in 11.2 liters of oxygen.

Under normal conditions, 1 mole of ideal gas assumes a volume of 22.4 liters.

N O2 = 11.2 / 22.4 = 0.5 mol;

With this amount of oxidizing agent, 1 mol of sodium oxide can be synthesized.

Let’s calculate its weight.

M Na2O = 23 x 2 + 16 = 62 grams / mol;

m Na2O = 62 x 1 = 62 grams;