Determine the mass of sodium spent on interaction with ethanol weighing 18.4 g

| April 19, 2021 | education

Determine the mass of sodium spent on interaction with ethanol weighing 18.4 g, and the volume of hydrogen evolved during the reaction.

First, we write down the equation of reactions.
2С2Н5 ОН + 2 Na = 2 C2H5ONa + H2.
Further, according to the reaction equation, we find the mass of sodium.
M (C2H5OH) = 12 × 2 + 5 + 16 + 1 = 46 g / mol.
M (Na) = 23 g / mol.
18.4 g C2H5OH – X g Na.
2 × 46 g / mol С2Н5ОН – 2 × 23 g / mol Na.
X = 18.4 x 2 x 23 ÷ (2 x 46) = 9.2 g sodium.
Next, we find the volume of hydrogen, for this we first calculate the mass of hydrogen.
18.4 g C2H5OH – X g H2.
2 × 46 С2Н5ОН – 2 g / mol Н2.
X = 18.4 × 2 ÷ (2 × 46) = 0.4 g of hydrogen.
Next, we find the volume of hydrogen.
n = m / M.
n = V / Vm.
m / M = V / Vm.
V = m × Vm ÷ M = 0.4 × 22.4 ÷ 2 = 4.48 liters.
Answer: the mass of sodium is 9.2 g. The volume of hydrogen is 4.48 liters.



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