Determine the mass of sodium that has reacted with ethyl alcohol if 5.6 liters of hydrogen were used.

1. Let’s compose the reaction equation:
2C2H5 – OH + 2Na = H2 + 2C2H5 – ONa – substitution reaction, hydrogen gas is released;
2. Let us determine the number of moles of H2, if its volume is known. We make a proportion based on Avogadro’s law:
2 mol (H2) – 22.4 L
X mol – 5.6 liters from here,
X mol (H2) = 5.6 * 1 / 22.4 = 0.25 mol;
3. Based on the proportion, we determine the amount of mol Na:
X mol (Na) – 0.25 mol (H2)
X mol (Na) = 2 * 0.25 / 1 = 0.5 mol;
4. Let’s calculate the mass of Na by the formula: Y (Na) = m (Na) / M (Na); Y (Na) = 0.5 * 22.9 = 11.45 g.
Answer: The mass of sodium is 11.45 g.