Determine the mass of sulfate ions in 20 g of 3% sodium sulfate solution.

univerkov | December 10, 2020 | education

mass of sodium sulfate = 20 * 0.03 = 0.6g
n (Na2SO4) = 0.6 / (23 * 2 + 32 + 16 * 4) = 4.22 * 10 ^ -3 mol
n (SO4 2-) = 4.22 * 10 ^ -3
m (SO4 2-) = 4.22 * 10 ^ -3 * (32 + 16 * 4) = 0.41 g

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