Determine the mass of sulfur that has reacted with O2 if 96 g of oxide S (lV) is formed according

Determine the mass of sulfur that has reacted with O2 if 96 g of oxide S (lV) is formed according to the equation S + O2 = SO2. a) how much oxygen will be consumed to burn 4g of sulfur?

The sulfur oxidation reaction is described by the following chemical equation:

S + O2 = SO2;

To obtain 1 mole of sulfur oxide, 1 mole of sulfur is required.

Let’s calculate the amount of substance in 96 grams of sulfur oxide.

M SO2 = 32 + 16 x 2 = 64 grams / mol;

N SO2 = 96/64 = 1.5 mol;

Let’s calculate the weight of the same amount of pure sulfur.

M S = 32 grams / mol;

m S = 32 x 1.5 = 48 grams;

Let’s calculate the amount of substance in 4 grams of sulfur.

M S = 32 grams / mol;

N S = 4/32 = 0.125 mol;

Let us calculate the volume of 0.125 mol of oxygen.

1 mole of ideal gas normally takes on a volume of 22.40 liters.

V O2 = 0.125 x 22.40 = 2.8 liters;