Determine the mass of sulfur that must be taken to react with oxygen to form 3.2 g of sulfur oxide (5)

The oxidation reaction of elemental sulfur with oxygen occurs in accordance with the following equation:

S + O2 = SO2;

When 1 mol of elemental sulfur is oxidized, 1 mol of gaseous oxide is synthesized. This is because the oxide molecule of this element contains 1 sulfur atom.

Let’s calculate the chemical amount of a substance contained in 3.2 grams of sulfur oxide.

M SO2 = 16 + 16 + 32 = 64.0 g / mol;

N SO2 = 3.2 / 64.0 = 0.050 mol;

Let us determine the weight of sulfur containing 0.05 mol of the substance.

Its molar mass is:

The weight of elemental sulfur will be equal to the product of the amount of the substance and its molar mass, which is 32 grams / mol.

m S = 0.05 x 32 = 1.6 grams;