Determine the mass of sulfuric acid formed from 400 g of sulfur (VI) oxide when it interacts with water.

1. Sulfur oxide reacts with water according to the equation:

SO3 + H2O = H2SO4;

2. Knowing the mass of the oxide, we find its chemical amount:

n (SO3) = m (SO3): M (SO3);

M (SO3) = 32 + 3 * 16 = 80 g / mol;

n (SO3) = 400: 80 = 5 mol;

3. All substances in the reaction equation are related as 1: 1: 1, that is, their quantities will be equal:

n (H2SO4) = n (SO3) = 5 mol;

4. Let’s calculate the mass of sulfuric acid:

m (H2SO4) = n (H2SO4) * M (H2SO4);

M (H2SO4) = 2 + 32 + 4 * 16 = 98 g / mol;

m (H2SO4) = 5 * 98 = 490 g.

Answer: 490