Determine the mass of sulfuric acid obtained by dissolving 40 g of SO3 in water, if the practical

Determine the mass of sulfuric acid obtained by dissolving 40 g of SO3 in water, if the practical reaction yield is 80% of the theoretical.

1.Let’s find the amount of substance SO3:

M (SO3) = 80 g / mol.

n = 40 g: 80 g / mol = 0.5 mol.

2.Let’s find the quantitative ratios of substances.

H2O + SO3 = H2SO4.

For 1 mole of SO3, there is a mole of H2SO4.

Substances are in quantitative ratios 1: 1.

The amount of substance will be equal.

n (H2SO4) = n (SO3) = 0.5 mol.

3.Let’s find the mass of H2SO4.

m = nM.

M (H2SO4) = 98 g / mol.

m = 0.5 mol × 98 g / mol = 49 g.

49 g – 100%,

x g – 80%,

x = (49g × 80%): 100% = 39.2g.

Answer: 39.2 g.