Determine the mass of sulfuric acid required to react with 70 g of sodium hydroxide?

univerkov | September 3, 2021 | education

Find the amount of NaOH.

M (NaOH) = 40 g / mol.

n = 70 g: 40 g / mol = 1.75 mol.

Let’s find the quantitative ratios of substances.

H2SO4 + 2NaOH = Na2SO4 + 2H2O.

For 2 mol of NaOH, there is 1 mol of H2SO4.

Substances are in quantitative ratios of 2: 1.

The amount of H2SO4 is 2 times less than the amount of NaOH.

n (H2SO4) = ½ n (NaOH) = 1.75: 2 = 0.875 mol.

Let’s find the mass of H2SO4.

m = nM.

M (H2SO4) = 98 g / mol.

m = 0.875 mol × 98 g / mol = 85.75 g.

Answer: 85.75 g.

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