Determine the mass of technical sulfur required to obtain 1774 liters. sulfur oxide (4), if the mass fraction

Determine the mass of technical sulfur required to obtain 1774 liters. sulfur oxide (4), if the mass fraction of impurities in technical sulfur is 10%. Process losses for the production of sulfur dioxide from sulfur are 12%.

The sulfur combustion reaction is described by the following chemical reaction equation:

S + O2 = SO2;

When 1 mol of sulfur is burned, 1 mol of its oxide is synthesized. This is due to the fact that the oxide molecule contains 1 sulfur atom.

Let’s calculate the chemical amount of the substance, which is in 1774 liters of sulfur oxide.

Under normal conditions, 1 mole of ideal gas assumes a volume of 22.4 liters.

N SO2 = 1774 / 22.4 = 79.20 mol;

Taking into account the proportion of impurities of 10% and technological losses of 12%, it is necessary to take 79.20 / 0.9 / 0.88 = 100 mol of sulfur;

The weight of the sulfur will be:

M S = 32 grams / mol;

m S = 100 x 32 = 3 200 grams;